If the number of solutions of ln ∣ sin x ∣ = − x 2 + 2 x when x ∈ ( 0 , π ) is m and when x ∈ [ − 2 π , 2 3 π ] is n , then ( m + n ) is equal to

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MathematicsFunctionsNumber of Solutions (graph)Medium2 minQB

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If the number of solutions of $ln ∣ sin x ∣ = - x^{2} + 2 x$ when $x \in (0, π)$ is $m$ and when $x \in [- \frac{π}{2}, \frac{3 π}{2}]$ is $n$ , then $(m + n)$ is equal to

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Answer:

Solution:

$m = 0, n = 2$ .

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Number of Solutions (graph)

⏱ 2mℹ️ Source: QB

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