The range of the function f ( x ) = ∣ x + 3∣ x + 3 , x  = − 3 is

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MathematicsFunctionsDomain-RangeEasy2 minQB

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The range of the function $f (x) = \frac{x + 3}{∣ x + 3∣}, x \neq = - 3$ is

Answer:

Solution:

$f (x) = 1$ when $x + 3 > 0$

$f (x) = - 1$ when $x + 3 < 0$

Range $= {- 1, 1}$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Domain-Range

⏱ 2mℹ️ Source: QB

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