If the functions of f and g are defined by f ( x ) = 3 − x , g ( x ) = 2 + 3 x for x ∈ R respectively, then g − 1 ( f − 1 ( 2 ) ) =

f − 1 ( x ) = 3 − x , g − 1 ( x ) = 3 x − 2 g − 1 [ f − 1 ( 2 ) ] = g − 1 ( 1 ) = − 3 1

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MathematicsFunctionsInverseEasy2 minQB

MathematicsEasysingle choice

If the functions of $f$ and $g$ are defined by $f (x) = 3 - x, g (x) = 2 + 3 x$ for $x \in R$ respectively, then $g^{- 1} (f^{- 1} (2)) =$

Answer:

Solution:

$f^{- 1} (x) = 3 - x, g^{- 1} (x) = \frac{x - 2}{3}$

$g^{- 1} [f^{- 1} (2)] = g^{- 1} (1) = - \frac{1}{3}$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Inverse

⏱ 2mℹ️ Source: QB

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