Let h ( x ) = ∣ kx + 5∣ , domain of f(x) is [- 5, 7], domain of f(h(x)) is [- 6, 1] and range of h(x) is the same as the domain of f(x), then value of k is

Question

TestHub · Accepted Answer

− 5 ≤ ∣ kx + 5∣ ≤ 7 ⇒ − 12 ≤ kx ≤ 2 where − 6 ≤ x ≤ 1 ⇒ − 6 ≤ 2 k ​ x ≤ 1 where − 6 ≤ x ≤ 1 ∴ k = 2 { ∵ range of h ( x ) = domain of f ( x )}

Mathematics - Functions Question with Solution | TestHub

Options:

Doubts & Discussion