Mathematics - Functions Question with Solution | TestHub

$$\begin{array}{rlrlrlrlrl}& =f(8y,-8x)& =f(8(-8x),-8(8y))=t(-64x,-64y)& =f(-64|-64x|,-64(-64y))& =f\left(2^{12}x,2^{12}y\right)f(x,y)& =f\left(2^{12}x,2^{12}y\right)f(x,0)& >f\left(2^{12}x,0\right)g(x)=& f\left(2^x,0\right)=f\left(2^{12}{2}^x,0\right)& =f\left(2^{x+12},0\right)& =g(x+12)\end{array}$$

$\Rightarrow g(x)=g(x+12)$ ⇒ period of $\mathrm{g}(\mathrm{x})$ in $12=T$

$\frac{T}{4}=3$