Equation of the locus of points equidistant from two points $(f (- 1), f (0), f (1))$ and $(f^{'} (1), f^{'} (- 2), f^{'} (2))$ where ' $f$ ' is a differentiable function satisfying the equation $f (x - f (y)) = f (f (y)) + x f (y) + f (x) - 1, \forall x, y \in R$
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Answer:
A
Solution:

Question

Equation of the locus of points equidistant from two points $(f (- 1), f (0), f (1))$ and $(f^{'} (1), f^{'} (- 2), f^{'} (2))$ where ' $f$ ' is a differentiable function satisfying the equation $f (x - f (y)) = f (f (y)) + x f (y) + f (x) - 1, \forall x, y \in R$

Options:

Answer:

A

Solution:

TestHub · Accepted Answer

Correct answer: A

Mathematics - Functions Question with Solution | TestHub

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