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MathematicsFunctionsMiscellaneous/MixedEasy2 minQB

MathematicsEasyinteger

$f$ is a function such that $f (x) + 2 f (1 - x) = x^{2} + 1$ . Value of $f (3)$ is

Answer:

Solution:

$f (x) + 2 f (1 - x) = x^{2} + 1$

$∴ f (1 - x) + 2 f (x) = (1 - x)^{2} + 1 = x^{2} - 2 x + 2$

Solving we get $3 f (x) = x^{2} - 4 x + 3$

$f (3) = 0$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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