Range of f ( x ) = 1 + s i n ( c o s x ) t a n ( π [ x 2 − x ] ) is (where [ x ] denotes the greatest integer function)

f ( x ) = 1 + s i n ( c o s x ) t a n ( π [ x 2 − x ] ) = { 0 } because of [ x 2 − x ] is integer.

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MathematicsFunctionsDomain-RangeMedium2 min

MathematicsMediumsingle choice

Range of $f (x) = \frac{t a n ( π [ x ^{2} - x ] )}{1 + s i n ( c o s x )}$ is (where $[x]$ denotes the greatest integer function)

Answer:

Solution:

$f (x) = \frac{t a n ( π [ x ^{2} - x ] )}{1 + s i n ( c o s x )} = {0}$ because of $[x^{2} - x]$ is integer.

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Domain-Range

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