Mathematics - Functions Question with Solution | TestHub

MathematicsFunctionsGeneral (Definition,type and special type)Medium2 minPYQ_2025

MathematicsMediumsingle choice

Let $[x]$ denote the greatest integer less than or equal to $x$ . Then the domain of $f (x) = sec^{- 1} (2 [x] + 1)$ is :

Options:

Answer:

Solution:

$f (x) = sec^{- 1} (2 [x] + 1) \Rightarrow 2 [x] + 1 \geq 1 \Rightarrow 2 [x] \geq 0 \Rightarrow [x] \geq 0 \Rightarrow x \geq 0 or 2 [x] + 1 \leq - 1 or 2 [x] \leq - 2 or [x] \leq - 1 or x \leq 0$
Domain of $f (x)$ is $(- \infty, \infty)$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:General (Definition,type and special type)

⏱ 2mℹ️ Source: PYQ_2025

Doubts & Discussion

Loading discussions...