Let f be a function such that f ( x ) + 3 f ( x 24 ) = 4 x , x  = 0 . Then f ( 3 ) + f ( 8 ) is equal to

f ( x ) + 3 f ( x 24 ) = 4 x Put x = 3 f ( 3 ) + 3 f ( 8 ) = 12 Put x = 8 f ( 8 ) + 3 f ( 3 ) = 32 Add both 4 ( f ( 3 ) + f ( 8 )) = 44 f ( 3 ) + f ( 8 ) = 11

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MathematicsFunctionsFunctional EquationEasy2 minPYQ_2025

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Let $f$ be a function such that $f (x) + 3 f (\frac{24}{x})$ $= 4 x, x \neq = 0$ . Then $f (3) + f (8)$ is equal to

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Answer:

Solution:

$f (x) + 3 f (\frac{24}{x}) = 4 x$
Put $x = 3 f (3) + 3 f (8) = 12$
Put $x = 8 f (8) + 3 f (3) = 32$
Add both $4 (f (3) + f (8)) = 44$
$f (3) + f (8) = 11$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Functional Equation

⏱ 2mℹ️ Source: PYQ_2025

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