Let f ( x ) = { − a x + a if if − a ≤ x ≤ 0 0 0 and g ( x ) = ( f ( x ∣ ) − ∣ f ( x ) ∣ ) /2 . Then the function g : [ − a , a ] → [ − a , a ] is

y = f ( x ) y = f ∣ x ∣ y = ∣ f ( x ) ∣ g ( x ) = 2 f ( ∣ x ∣ ) − ∣ f ( x ) ∣

Mathematics - Functions Question with Solution | TestHub

MathematicsFunctionsTypes of Function (Mapping)Hard2 minPYQ_2024

MathematicsHardsingle choice

Let $f (x) = {- a x + a if if - a \leq x \leq 0 0 < x \leq a$ where $a > 0$ and $g (x) = (f (x ∣) - ∣ f (x) ∣) /2$ . Then the function $g : [- a, a] \to [- a, a]$ is

Options:

Answer:

Solution:

$y = f (x)$
$y = f ∣ x ∣$
$y = ∣ f (x) ∣$
$g (x) = \frac{f ( ∣ x ∣ ) - ∣ f ( x ) ∣}{2}$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Types of Function (Mapping)

⏱ 2mℹ️ Source: PYQ_2024

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