If f ( x ) = 1 + x 2 x , then (fof of) ( x ) is

f ( x ) = 1 + x 2 x fof = 1 + 1 + x 2 x 2 1 + x 2 x = 2 x 2 + 1 x fofof = 1 + 2 x 2 + 1 x 2 2 x 2 + 1 x = 1 + 3 x 2 x

Mathematics - Functions Question with Solution | TestHub

MathematicsFunctionsCompositeEasy2 minPYQ_2023

MathematicsEasysingle choice

If $f (x) = \frac{x}{1 + x ^{2}}$ , then (fof of) $(x)$ is

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Answer:

Solution:

$f (x) = \frac{x}{1 + x ^{2}}$
fof $= \frac{\frac{x}{1 + x ^{2}}}{1 + \frac{x ^{2}}{1 + x ^{2}}} = \frac{x}{2 x ^{2} + 1}$
fofof $= \frac{\frac{x}{2 x ^{2} + 1}}{1 + \frac{x ^{2}}{2 x ^{2} + 1}} = \frac{x}{1 + 3 x ^{2}}$

Stream:BITSATSubject:MathematicsTopic:FunctionsSubtopic:Composite

⏱ 2mℹ️ Source: PYQ_2023

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