The domain of the function f ( x ) = lo g 2 ( − lo g 1/2 ( 1 + x 1/4 1 ) − 1 ) is

f ( x ) is defined if − lo g 1/2 ( 1 + x 1/4 1 ) − 1 > 0 ⇒ lo g 1/2 ( 1 + x 1/4 1 ) ( 2 1 ) − 1 ⇒ x 1/4 1 > 1 ⇒ 0 < x < 1

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MathematicsFunctionsDomain-RangeMedium2 minPYQ_2014

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The domain of the function $f (x) = lo g_{2} (- lo g_{1/2} (1 + \frac{1}{x ^{1/4}}) - 1)$ is

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$f (x)$ is defined if $- lo g_{1/2} (1 + \frac{1}{x ^{1/4}}) - 1 > 0 \Rightarrow lo g_{1/2} (1 + \frac{1}{x ^{1/4}}) < - 1 \Rightarrow 1 + \frac{1}{x ^{1/4}} > (\frac{1}{2})^{- 1} \Rightarrow \frac{1}{x ^{1/4}} > 1 \Rightarrow 0 < x < 1$

Stream:BITSATSubject:MathematicsTopic:FunctionsSubtopic:Domain-Range

⏱ 2mℹ️ Source: PYQ_2014

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