Let f ( x ) = ( x + 1 ) 2 − 1 , x ≥ − 1 Statement-1: The set { x : f ( x ) = f − 1 ( x ) } = { 0 , − 1 } Statement-2 : f is a bijection.

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MathematicsFunctionsInverseMedium2 minPYQ_2009

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Let $f (x) = (x + 1)^{2} - 1, x \geq - 1$ Statement-1: The set ${x : f (x) = f^{- 1} (x)} = {0, - 1}$ Statement-2 : $f$ is a bijection.

Answer:

Solution:

There is no information about co-domain therefore $f (x)$ is not necessarily onto.

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Inverse

⏱ 2mℹ️ Source: PYQ_2009

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