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MathematicsFunctionsEven-oddEasy2 minPYQ_2003

MathematicsEasysingle choice

The function $f (x) = lo g (x + x^{2} + 1)$ , is

Answer:

Solution:

$f (x) = lo g (x + x^{2} + 1)$ $f (- x) = - lo g (x + x^{2} + 1)$ $f (- x) = - f (x)$ , i.e., $f (x)$ is an odd function.

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Even-odd

⏱ 2mℹ️ Source: PYQ_2003

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