Let P be a point on ellipse 9 x 2 + 7 y 2 = 1 whose parametric angle is π /4 , then abscissa of the incentre of triangle SPS 1 is

Incentre of △ SPS 1 is ( ae cos θ , 1 + e be s i n θ ) ⇒ its abscissa = ae cos θ = 9 − 7 × 2 1 = 1

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MathematicsEllipseGeneralEasy2 minQB

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Let P be a point on ellipse $\frac{x ^{2}}{9} + \frac{y ^{2}}{7} = 1$ whose parametric angle is $π /4$ , then abscissa of the incentre of triangle $SPS^{1}$ is

Answer:

Solution:

Incentre of $△ SPS^{1}$ is $(ae cos θ, \frac{be s i n θ}{1 + e})$

$\Rightarrow its abscissa = ae cos θ = 9 - 7 \times \frac{1}{2} = 1$

Stream:JEESubject:MathematicsTopic:EllipseSubtopic:General

⏱ 2mℹ️ Source: QB

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