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MathematicsEllipseTangent to ellipseHard2 minPYQ_2017
MathematicsHardmatching list

Columns 1, 2 and 3 contain conics, equations of tangents to the conics and points of contact, respectively.

Column 1Column 2Column 3
(I) x2+y2=a2(i) my=m2x+a(P) am2,2am
(II) x2+a2y2=a2(ii) y=mx+a m2+1(Q) -mam2+1,am2+1
(III) y2=4ax(iii) y=mx+ a2m2-1(R) -a2ma2m2+1,1a2m2+1
(IV) x2-a2y2=a2(iv) y=mx+a2m2+1(S) -a2ma2m2-1,-1a2m2-1

Fora=2, if a tangent is drawn to a suitable conic (Column 1) at the point of contact-1, 1, then which of the following options is the only Correct combination for obtaining its equation?

Options:

Answer:
C
Solution:

For a= 2  and point (-1, 1) only I of column-1 satisfies. Hence, equation of tangent is -x+y=2 or  y=x+2    m=1  which matches with (ii) of column 2 and also with Q of column 3

Stream:JEE_ADVSubject:MathematicsTopic:EllipseSubtopic:Tangent to ellipse
2mℹ️ Source: PYQ_2017

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