The solution of x 3 d x d y + 4 x 2 tan y = e x sec y satisfying y ( 1 ) = 0 is sin y = e x ( x − 1 ) x − k then k =

Question

The solution of x 3 d x d y ​ + 4 x 2 tan y = e x sec y satisfying y ( 1 ) = 0 is sin y = e x ( x − 1 ) x − k then k =

TestHub · Accepted Answer

Put sin y = t ⇒ cos y d x d y ​ = d x d t ​ ​ ∴ dx dt ​ + x 4 ​ t = x 3 e x ​ I . F . = e ∫ 4/ x d x = e 4 l n x = x 4 dx d ( t ⋅ x 4 ) ​ = x e x ​

Mathematics - Differential Equation Question with Solution | TestHub