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MathematicsDifferential EquationLinear DE / Red. LDEHard2 minPYQ_2021
MathematicsHardnumerical range

Ify=yxis the solution of the equationesinycosydydx+esinycosx=cosx,y0=0; then1+yπ6+32yπ3+12yπ4is equal to _______.

Answer:
1.00
Solution:

Putesiny=t

esinycosydydx=dtdx

D.E is dtdx+tcosx=cosx

I.F.=ecosxdx=esinx

solution is t.esinx=cosxesinx

esinyesinx=esinx+c

 x=0,y=0c=0

esiny=1

y=0

1+yπ6+32yπ3+12yπ4=1

Stream:JEESubject:MathematicsTopic:Differential EquationSubtopic:Linear DE / Red. LDE
2mℹ️ Source: PYQ_2021

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