Mathematics - Differential Equation Question with Solution | TestHub

$ydx-xdy=2y^{2}dy$

$\frac{ydx-xdy}{y^2}=2dy$

$d\left(\frac{x}{y}\right)=2dy$

$\int d\left(\frac{x}{y}\right)=2\int dy$

$\frac{x}{y}=2y+c$

$x=2y^2+cy$

If$y=\mathrm{ }-1,\mathrm{ }x=1$

$1=2-c$

$c=1$

$\therefore$Curve would be

$x=2y^2+y$

If$y=1$then$x=3$.