The degree of the differential equation ( d x 3 d 3 y ) 2/3 + 4 − 3 d x 2 d 2 y + 5 d x d y = 0 is

( d x 3 d 3 y ) 2/3 + 4 − 3 d x 2 d 2 y + 5 d x d y = 0 ⇒ ( d x 3 d 3 y ) 2 = [ 3 d x 2 d 2 y − 5 d x d y − 4 ] 3 It is a differential equation of degree 2.

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MathematicsDifferential EquationGeneral (Order/degree/formation)Medium2 minPYQ_2011

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The degree of the differential equation $(\frac{d ^{3} y}{d x ^{3}})^{2/3} + 4 - 3 \frac{d ^{2} y}{d x ^{2}} + 5 \frac{d y}{d x} = 0$ is

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$(\frac{d ^{3} y}{d x ^{3}})^{2/3} + 4 - 3 \frac{d ^{2} y}{d x ^{2}} + 5 \frac{d y}{d x} = 0 \Rightarrow (\frac{d ^{3} y}{d x ^{3}})^{2} = [3 \frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} - 4]^{3}$ It is a differential equation of degree 2.

Stream:BITSATSubject:MathematicsTopic:Differential EquationSubtopic:General (Order/degree/formation)

⏱ 2mℹ️ Source: PYQ_2011

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