Mathematics - Differential Equation Question with Solution | TestHub

MathematicsDifferential EquationLinear DE / Red. LDEMedium2 minPYQ_2009

MathematicsMediumsingle choice

Area of the triangle formed by the line $x + y = 3$ and angle bisectors of the pair of straight lines $x^{2} - y^{2} + 2 y = 1$ is

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Answer:

Solution:

$x^{2} - y^{2} + 2 y = 1 \Rightarrow x = \pm (y - 1)$ Bisectors of above line are $x = 0 & y = 1$
So area between $x = 0, y = 1 & x + y = 3$ is shaded Region shown in figure.
Area $= 1/2 \times 2 \times 2 = 2$ sq. units

Stream:BITSATSubject:MathematicsTopic:Differential EquationSubtopic:Linear DE / Red. LDE

⏱ 2mℹ️ Source: PYQ_2009

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