Two fair dice are thrown. The numbers on them are taken as $λ$ and $μ,$ and a system of linear equations
$x + y + z = 5$
$x + 2 y + 3 z = μ$
$x + 3 y + λ z = 1$
is constructed. If $p$ is the probability that the system has a unique solution and $q$ is the probability that the system has no solution, then:

Question

Two fair dice are thrown. The numbers on them are taken as $λ$ and $μ,$ and a system of linear equations
$x + y + z = 5$

$x + 2 y + 3 z = μ$

$x + 3 y + λ z = 1$
is constructed. If $p$ is the probability that the system has a unique solution and $q$ is the probability that the system has no solution, then:

TestHub · Accepted Answer

1 1 1 1 2 3 1 3 λ = λ - 5 Δ 1 = 1 1 5 2 3 μ 3 λ 1 = 10 λ + 3 μ - λμ - 44 Δ 2 = 1 1 5 1 3 μ 1 λ 1 = 5 λ + μ - λμ - 13 Δ 3 = 1 1 5 1 2 μ 1 3 1 = - 2 μ + 6 For unique solution λ ≠ 5 , μ ∈ { 1 , 2 , 3 , 4 , 5 , 6 } ⇒ p = 5 6 × 1 = 5 6 For No Solution λ = 5 , μ ≠ 3 ⇒ q = 1 6 × 5 6 = 5 36

Mathematics - Determinant Question with Solution | TestHub

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