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Mathematics - Determinant Question with Solution | TestHub

MathematicsDeterminantProperties of det.Medium2 minPYQ_2021
MathematicsMediumsingle choice

The maximum value of fx=sin2x1+cos2xcos2x1+sin2xcos2xcos2xsin2xcos2xsin2x, xR is

Options:

Answer:
C
Solution:

fx=sin2x1+cos2xcos2x1+sin2xcos2xcos2xsin2xcos2xsin2x, xR

C1C1+C2

=21+cos2xcos2x2cos2xcos2x1cos2xsin2x

R1R1-R2

=0102cos2xcos2x1cos2xsin2x

Expanding w.r.t. R1

=-2sin2x-cos2x

So, fx=cos2x-2sin2x

fxmax=1+4=5

Stream:JEESubject:MathematicsTopic:DeterminantSubtopic:Properties of det.
2mℹ️ Source: PYQ_2021

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