If D = 1 1 1 1 1 + x 1 1 1 1 + y for x  = 0 , y  = 0 then D is

D = 1 1 1 1 1 + x 1 1 1 1 + y C 2 → C 2 − C 1 \& C 3 → C 3 − C 1 1 1 1 0 x 0 0 0 y = x y . Hence D is divisible by both x and y .

Mathematics - Determinant Question with Solution | TestHub

MathematicsDeterminantProperties of det.Medium2 minPYQ_2007

MathematicsMediumsingle choice

If $D = 111 1 1 + x 1 11 1 + y$ for $x \neq = 0, y \neq = 0$ then $D$ is

Options:

Answer:

Solution:

$D = 111 1 1 + x 1 11 1 + y$ $C_{2} \to C_{2} - C_{1}$ \& $C_{3} \to C_{3} - C_{1}$ $111 0 x 0 00 y = x y$ . Hence $D$ is divisible by both $x$ and $y$ .

Stream:JEESubject:MathematicsTopic:DeterminantSubtopic:Properties of det.

⏱ 2mℹ️ Source: PYQ_2007

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