If ∫ 0 π /4 tan 5 x d x = k 1 lo g 2 − 4 1 then k =

∫ 0 π /4 tan 5 x d x = 4 1 − 2 1 + 2 1 lo g 2 = 2 1 lo g 2 − 4 1

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$If \int_{0}^{π /4} tan^{5} x d x = \frac{1}{k} lo g 2 - \frac{1}{4} then k =$

Answer:

Solution:

$\int_{0}^{π /4} tan^{5} x d x = \frac{1}{4} - \frac{1}{2} + \frac{1}{2} lo g 2 = \frac{1}{2} lo g 2 - \frac{1}{4}$

Stream:JEESubject:MathematicsTopic:Definite IntegrationSubtopic:Reduction formula

⏱ 2mℹ️ Source: QB

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