For k ∈ N , let b k = ∫ 1 e ( k + l o g x ) ( k + 1 + l o g x ) 1 x d x and a n = ∑ k = 1 n b k . Then which of the following options is/are correct

Mathematics - Definite Integration Question with Solution | TestHub

MathematicsDefinite IntegrationDefinite Integration by SubstitutionMedium2 minQB

MathematicsMediummultiple choice

For $k \in N$ , let $b_{k} = \int_{1}^{e} \frac{1}{( k + l o g x ) ( k + 1 + l o g x )} \frac{d x}{x}$ and $a_{n} = \sum_{k = 1}^{n} b_{k}$ . Then which of the following options is/are correct

Options:(select one or more)

Answer:

A, B, C, D

Solution:

Stream:JEESubject:MathematicsTopic:Definite IntegrationSubtopic:Definite Integration by Substitution

⏱ 2mℹ️ Source: QB

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