Mathematics - Definite Integration Question with Solution | TestHub

$${\int }_{-3}^{-2}f(x)dx+{\int }_{-2}^{-1}f(x)dx+{\int }_{-1}^{0}f(x)dx+{\int }_0^{1}f(x)dx+{\int }_1^{2}f(x)dx+{\int }_2^{3}f(x)dx$$

$$=(9-3)+(4-2)+(1-1)+(0+0)+(1+1)+(4+2)$$

$$=6+2+0+0+2+6$$

$$=16$$