Mathematics - Definite Integration Question with Solution | TestHub

$I={\int }_0^{1}1\cdot {\left(1-x^{10}\right)}^{20}dx$ $x^{10}=t$ $x=t^{1/10}$ $dx=\frac{1}{10}(t{)}^{-9/10}dt$ $I={\int }_0^1(1-t{)}^{20}\frac{1}{10}(t{)}^{-9/10}dt$ $I=\frac{1}{10}{\int }_0^1{t}^{-9/10}(1-t{)}^{20}dt$ $a=\frac{1}{10}b=\frac{1}{10}c=21$