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Mathematics - Definite Integration Question with Solution | TestHub

MathematicsDefinite IntegrationDefinite Integration by SubstitutionMedium2 minPYQ_2022
MathematicsMediumsingle choice

The integral0π213+2sinx+cosxdxis equal to:

Options:

Answer:
B
Solution:

Given,

I=0π2dx3+2sinx+cosx

I=0π2dx3+22tanx21+tan2x2+1-tan2x21+tan2x2

I=0π2sec2x2·dx2tan2x2+4tanx2+4

Put tanx2=t 12sec2x2dx=dt, so

I=01dtt+12+1

I=tan-1t+101

I=tan-12-π4

Stream:JEESubject:MathematicsTopic:Definite IntegrationSubtopic:Definite Integration by Substitution
2mℹ️ Source: PYQ_2022

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