TestHub
TestHub

Mathematics - Definite Integration Question with Solution | TestHub

MathematicsDefinite IntegrationDerivatives (Newton- Leibnitz)Medium2 minPYQ_2021
MathematicsMediumsingle choice

Letf : RRbe a continuous function. Thenlimxπ/4π42sec2xf(x)dxx2-π216is equal to:

Options:

Answer:
C
Solution:

 limxπ4π42sec2xfxdxx2-π216

Using L-Hospital's rule, we get

 =limxπ4π4fsec2x·2·secx·secx·tanx-02x

=π4·2(2)2·(1)·f(2)2·π4

=2f2

Stream:JEESubject:MathematicsTopic:Definite IntegrationSubtopic:Derivatives (Newton- Leibnitz)
2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...