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MathematicsDefinite IntegrationMiscellaneous/MixedHard2 minPYQ_2015
MathematicsHardsingle choice

Letf:(-1, 1)Rbe a continuous function. If0sinxf(t) dt=32x,thenf32is equal to:

Options:

Answer:
B
Solution:

0sinxftdt= 32 x.

Differentiating w.r.txboth the sides,

fsinx·cosx= 32

Putx= π 3.

12·f 32=32

f32=3.

Stream:JEESubject:MathematicsTopic:Definite IntegrationSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2015

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