Statement - I : The value of the integral ∫ π / 6 π / 3 d x 1 + tan x is equal to π 6 . Statement - II : ∫ a b f x d x = ∫ a b f a + b - x d x .

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Statement II is a standard property of definite integrals. For statement I : I = ∫ π / 6 π / 3 d x 1 + tan x = ∫ π / 6 π / 3 d x 1 + cot x I = ∫ π / 6 π / 3 tan x 1 + tan x d x = ∫ π / 6 π / 3 sin x cos x + sin x d x = ∫ π / 6 π / 3 cos x cos x + sin x d x 2 I = ∫ π / 6 π / 3 d x 2 I = π 3 - π 6 I = π 1 2 Hence, statement I is false.

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