Find the value of ∫ 0 4 π ∣ sin x ∣ d x

We know that ∣ sin x ∣ is a periodic function of π Hence ∫ 0 4 π ∣ sin x ∣ d x = 4 ∫ 0 π ∣ sin x ∣ d x = 4 ∫ 0 π sin x d x = 4 [ − cos x ] 0 π = 8

Mathematics - Definite Integration Question with Solution | TestHub

MathematicsDefinite IntegrationProperties of definite integrationEasy2 minPYQ_2011

MathematicsEasysingle choice

Find the value of $\int_{0}^{4 π} ∣ sin x ∣ d x$

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We know that $∣ sin x ∣$ is a periodic function of $π$ $Hence \int_{0}^{4 π} ∣ sin x ∣ d x = 4 \int_{0}^{π} ∣ sin x ∣ d x = 4 \int_{0}^{π} sin x d x = 4 [- cos x]_{0}^{π} = 8$

Stream:BITSATSubject:MathematicsTopic:Definite IntegrationSubtopic:Properties of definite integration

⏱ 2mℹ️ Source: PYQ_2011

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