The value of the integral, ∫ 3 6 9 − x + x x d x is

I = ∫ 3 6 9 − x + x x d x I = ∫ 3 6 9 − x + x 9 − x d x 2 I = ∫ 3 6 d x = 3 ⇒ I = 2 3

Mathematics - Definite Integration Question with Solution | TestHub

MathematicsDefinite IntegrationProperties of definite integrationEasy2 minPYQ_2006

MathematicsEasysingle choice

The value of the integral, $\int_{3}^{6} \frac{x}{9 - x + x} d x$ is

Answer:

Solution:

$I = \int_{3}^{6} \frac{x}{9 - x + x} d x$ $I = \int_{3}^{6} \frac{9 - x}{9 - x + x} d x$ $2 I = \int_{3}^{6} d x = 3 \Rightarrow I = \frac{3}{2}$

Stream:JEESubject:MathematicsTopic:Definite IntegrationSubtopic:Properties of definite integration

⏱ 2mℹ️ Source: PYQ_2006

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