The value of ∫ − 2 3 1 − x 2 d x is

∫ − 2 − 1 ( x 2 − 1 ) d x + ∫ − 1 1 ( 1 − x 2 ) d x + ∫ 1 3 ( x 2 − 1 ) d x = 3 x 3 − x ∣ − 2 − 1 + x − 3 x 3 − 1 1 + 3 x 3 − x ∣ 1 3 = 3 28

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Mathematics - Definite Integration Question with Solution | TestHub

MathematicsDefinite IntegrationProperties of definite integrationMedium2 minPYQ_2004

MathematicsMediumsingle choice

The value of $\int_{- 2}^{3} 1 - x^{2} d x$ is

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Solution:

$\int_{- 2}^{- 1} (x^{2} - 1) d x + \int_{- 1}^{1} (1 - x^{2}) d x + \int_{1}^{3} (x^{2} - 1) d x = \frac{x ^{3}}{3} - x ∣_{- 2}^{- 1} + x - \frac{x ^{3}}{3}_{- 1}^{1} + \frac{x ^{3}}{3} - x ∣_{1}^{3} = \frac{28}{3}$

Stream:JEESubject:MathematicsTopic:Definite IntegrationSubtopic:Properties of definite integration

⏱ 2mℹ️ Source: PYQ_2004

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