Mathematics - Coordinate Geometry Mixed Question with Solution | TestHub
The consistent second-degree equation (a₁x+b₁y+c₁)(a₂x+b₂y+c₂)=k, where a₁b₁c₁a₂b₂c₂k≠0, describes a conic. Match each condition to its type.
List I | List II |
(A) a₁/a₂=b₁/b₂=c₁/c₂ | (P) Parabola |
(B) a₁/a₂=b₁/b₂≠c₁/c₂ | (Q) Hyperbola |
(C) a₁/a₂≠b₁/b₂ | (R) Pair of lines |
(D) a₁a₂+b₁b₂=0 | (S) Circle |
Options:
Answer:
Solution:
(A),(B) Parallel factors reduce the equation to a quadratic in one linear coordinate. Real consistency gives a pair of parallel lines, possibly coincident. (C) Nonparallel factors give independent linear coordinates U,V after shifting to their intersection. UV=k with k≠0 is a hyperbola. (D) The nonzero normals are perpendicular, so the factors are nonparallel and the hyperbola is rectangular. Thus A-R, B-R, C-Q, D-Q.
