Consider the function f ( x ) = x 2 + b x + c , where D = b 2 − 4 c 0 Column – I Condition on b and c Column – II Number of points of non- differentiability of g(x) = |f(|x|)| (C) c = 0 , b 0 (p)

Question

Consider the function f ( x ) = x 2 + b x + c , where D = b 2 − 4 c > 0 Column – I Condition on b and c Column – II Number of points of non- differentiability of g(x) = |f(|x|)| (C) c = 0 , b > 0 (p) 1 (D) b = 0 , c < 0 (q) 2 (A) b < 0 , c > 0 (r) 3 (B) c = 0 , b < 0 (s) 5 List - I List - II (C) c = 0 , b > 0 (p) 1 (D) b = 0 , c < 0 (q) 2 (A) b < 0 , c > 0 (r) 3 (B) c = 0 , b < 0 (s) 5

TestHub · Accepted Answer

Correct answer: A

Column – I Condition on b and c	Column – II Number of points of non- differentiability of g(x) = \|f(\|x\|)\|
(C) $c = 0, b > 0$	(p) 1
(D) $b = 0, c < 0$	(q) 2
(A) $b < 0, c > 0$	(r) 3
(B) $c = 0, b < 0$	(s) 5

List - I	List - II
(C) $c = 0, b > 0$	(p) 1
(D) $b = 0, c < 0$	(q) 2
(A) $b < 0, c > 0$	(r) 3
(B) $c = 0, b < 0$	(s) 5

Mathematics - Continuity - Differentiability Question with Solution | TestHub

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