Let f ( x ) be the determinant e 2 x ln ( 1 − x ) x + x 2 sin x sin ( 3 x 3 ) cos 2 x cos ( x 2 ) e − x 2 x 4 + x 8 . Find ∣ f ′ ( 0 ) ∣ /2 .

Question

Let f ( x ) be the determinant ​ e 2 x ln ( 1 − x ) x + x 2 ​ sin x sin ( 3 x 3 ) cos 2 x ​ cos ( x 2 ) e − x 2 x 4 + x 8 ​ ​ . Find ∣ f ′ ​ ( 0 ) ∣ /2 .

TestHub · Accepted Answer

The coefficient of x in the determinant is -3 , so f ′ ( 0 ) = − 3 . Hence ∣ f ′ ( 0 ) ∣/2 = 3/2 = 1.50 .

Mathematics - Continuity - Differentiability Question with Solution | TestHub

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