Define f : [ 0 , π ] → R by is continuous at x = 2 π , then k =

Let sin x = t and evaluate lim t → 1 1 − t 2 t 2 [ 2 t 2 + 3 t + 4 − t 2 + 6 t + 2 ] by rationalization

Mathematics - Continuity - Differentiability Question with Solution | TestHub

MathematicsContinuity - DifferentiabilityMiscellaneous/MixedMedium2 minQB

MathematicsMediumsingle choice

Define $f : [0, π] \to R$ by is continuous at $x = \frac{π}{2}$ , then $k =$

Answer:

Solution:

Let $sin x = t$ and evaluate $lim_{t \to 1} \frac{t ^{2}}{1 - t ^{2}} [2 t^{2} + 3 t + 4 - t^{2} + 6 t + 2]$ by rationalization

Stream:JEESubject:MathematicsTopic:Continuity - DifferentiabilitySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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