Let f ( x ) = { ( x − 1 ) 2 x 2 32 − 2 32 ⋅ x + 4 16 − 1 , x  = 1 k , x = 1 . Then value of k so that the function is continuous at x = 1 is

For continuity at x = 1 , lim x → 1 f ( x ) = f ( 1 ) = k . Use L'Hopital's Rule twice. k = 2 63 − 2 31

Mathematics - Continuity - Differentiability Question with Solution | TestHub

MathematicsContinuity - DifferentiabilityContinuity- MiscellaneousEasy2 minQB

MathematicsEasymultiple choice

Let $f (x) = {\frac{x ^{2^{32}} - 2 ^{32} \cdot x + 4 ^{16} - 1}{( x - 1 ) ^{2}}, x \neq = 1 k, x = 1$ .

Then value of k so that the function is continuous at x = 1 is

Answer:

A,C

Solution:

For continuity at $x = 1$ , $lim_{x \to 1} f (x) = f (1) = k$ .

Use L'Hopital's Rule twice.

$k = 2^{63} - 2^{31}$

Stream:JEESubject:MathematicsTopic:Continuity - DifferentiabilitySubtopic:Continuity- Miscellaneous

⏱ 2mℹ️ Source: QB

Loading discussions...