Mathematics - Continuity - Differentiability Question with Solution | TestHub
MathematicsContinuity - DifferentiabilityContinuity- MiscellaneousMedium2 minQB
MathematicsMediumsingle choice
A function is defined by ,
Options:
Answer:
B
Solution:
f(x) = \left\{ {\matrix{
{{{[{x^2}] - 1} \over {{x^2} - 1}},} & {for\,\,{x^2} \ne 1} \cr
{0\,\,\,\,\,\,\,\,\,\,\,\,\,,} & {for\,{x^2} = 1} \cr
} } \right.= \left\{ {\matrix{
{{{ - 1} \over {{x^2} - 1}},} & {for\,0\,\, < {x^2} < 1} \cr
\matrix{
\,0,\,\,\,\,\,\, \hfill \cr
\,0, \hfill \cr} & \matrix{
for\,{x^2} = 1 \hfill \cr
for\,\,1 < {x^2} < 2 \hfill \cr} \cr
} } \right.
RHL at x = 1 is 0
Also LHL at x = 1 is
Stream:JEESubject:MathematicsTopic:Continuity - DifferentiabilitySubtopic:Continuity- Miscellaneous
⏱ 2mℹ️ Source: QB
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