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Mathematics - Continuity - Differentiability Question with Solution | TestHub

MathematicsContinuity - DifferentiabilityDifferentiabilityHard2 minPYQ_2020
MathematicsHardnumerical

Letf:RRbe defined asfx=x5sin1x+5x2,x<00,x=0x5cos1x+λx2,x>0. The value ofλfor whichf"(0)exists, is___.

Answer:
5.00
Solution:

fx=5x4·sin(1/x)-x3cos(1/x)+10x,x<00,x=05x4·cos(1/x)+x3sin(1/x)+2λx,x>0
Differentiating two times.f"x=20x3·sin(1/x)-5x2cos(1/x)-3x2cos(1/x)-xsin(1/x)+10, x<020x3·cos(1/x)+5x2sin(1/x)+3x2sin(1/x)-xcos(1/x)+2λ, x>0
f"0+=f"0-
2λ=10  λ=5

Stream:JEESubject:MathematicsTopic:Continuity - DifferentiabilitySubtopic:Differentiability
2mℹ️ Source: PYQ_2020

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