Let f : - 1 , 1 → R be a function defined by f x = m a x - x , - 1 - x 2 . If K be the set of all points at which f is not differentiable, then K has exactly

From the graph, it can be concluded that f x is non-differentiable at x = 0 , ± 1 2 in - 1 , 1 . ∴ At 3 points in - 1 , 1 .

Mathematics - Continuity - Differentiability Question with Solution | TestHub

MathematicsContinuity - DifferentiabilityDifferentiabilityEasy2 minPYQ_2019

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Let $f : (- 1, 1) \to R$ be a function defined by $f (x) = m a x \{- |x|, - \sqrt{1 - x^{2}}\} .$ If $K$ be the set of all points at which $f$ is not differentiable, then $K$ has exactly

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Solution:

From the graph, it can be concluded that $f (x)$ is non-differentiable at $x = 0, \pm \frac{1}{\sqrt{2}}$ in $(- 1, 1)$ .

$∴$ At $3$ points in $(- 1, 1)$ .

Stream:JEESubject:MathematicsTopic:Continuity - DifferentiabilitySubtopic:Differentiability

⏱ 2mℹ️ Source: PYQ_2019

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