The number of points at which the function f ( x ) = l o g ∣ x ∣ 1 is discontinuous is:

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MathematicsContinuity - DifferentiabilityContinuity- MiscellaneousEasy2 minPYQ_2016

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The number of points at which the function $f (x) = \frac{1}{l o g ∣ x ∣}$ is discontinuous is:

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Answer:

Solution:

The function $lo g ∣ x ∣$ is not defined at $x = 0$ , so, $x = 0$ is a point of discontinuity. Also for $f (x)$ to be defined, $lo g ∣ x ∣ \neq = 0 \Rightarrow x \neq = \pm 1$ Hence, 0,1,-1 are three points of discontinuity.

Stream:BITSATSubject:MathematicsTopic:Continuity - DifferentiabilitySubtopic:Continuity- Miscellaneous

⏱ 2mℹ️ Source: PYQ_2016

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