Let ∣ z 1 − 8 − 2 i ∣ ≤ 1 and ∣ z 2 − 2 + 6 i ∣ ≤ 2 , z 1 , z 2 ∈ C . Then the minimum value of ∣ z 1 − z 2 ∣ is :

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MathematicsComplex NumberGeneral(Modulus,Argument,Conjugate)Medium2 minPYQ_2025

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Let $∣ z_{1} - 8 - 2 i ∣ \leq 1$ and $∣ z_{2} - 2 + 6 i ∣ \leq 2, z_{1}, z_{2} \in C$ . Then the minimum value of $∣ z_{1} - z_{2} ∣$ is :

Answer:

Solution:

$∵ AB = 100 = 10 ∴ ∣ Z_{1} - Z_{2} ∣_{m i n} = 10 - 2 - 1 = 7$

Stream:JEESubject:MathematicsTopic:Complex NumberSubtopic:General(Modulus,Argument,Conjugate)

⏱ 2mℹ️ Source: PYQ_2025

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