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MathematicsComplex NumberGeneral(Modulus,Argument,Conjugate)Medium2 minPYQ_2017
MathematicsMediumsingle choice

The equationImiz-2z-i+1=0, zC, zirepresents a part of a circle having radius equal to :

Options:

Answer:
A
Solution:

Let z=x+iy, then

Im ix-y-2x+y-1i x-y-1ix-y-1i+1=y-1 y+2+x2x2+y-12+1=0

2x2+2y2-y-1=0

x2+y2-y2-12=0

Center (0, 14)

Radius =g2+f2-c

Radius= 116+12= 916=34

Stream:JEESubject:MathematicsTopic:Complex NumberSubtopic:General(Modulus,Argument,Conjugate)
2mℹ️ Source: PYQ_2017

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