Mathematics - Complex Number Question with Solution | TestHub

MathematicsComplex NumberGeneral(Modulus,Argument,Conjugate)Easy2 minPYQ_2015

MathematicsEasysingle choice

The root of the equation $2 (1 + i) x^{2} - 4 (2 - i) x - 5 - 3 i = 0$ which has greater modulus is

Options:

Answer:

Solution:

$Roots = \frac{4 ( 2 - i ) \pm 16 ( 2 - i ) ^{2} + 8 ( 1 + i ) ( 5 + 3 i )}{4 ( 1 + i )} = \frac{4 - i}{1 + i} or \frac{- i}{1 + i} = \frac{3 - 5 i}{2} or \frac{- 1 - i}{2}$

Stream:BITSATSubject:MathematicsTopic:Complex NumberSubtopic:General(Modulus,Argument,Conjugate)

⏱ 2mℹ️ Source: PYQ_2015

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