Mathematics - Circle Question with Solution | TestHub

MathematicsCircleGeneral, Basic geometries, Definition Diametrical form of circleMedium2 minQB

MathematicsMediumsingle choice

Passage / Comprehension

P is a variable point on the line L = 0. Tangents from P touch the circle x² + y² = 4 at Q and R. The parallelogram PQSR is completed.

A variable point $P$ lies on the line $L = 0$ . Tangents from $P$ touch the circle $x^{2} + y^{2} = 4$ at $Q, R$ , and parallelogram $PQSR$ is completed. If $L$ is $y - 4 = 0$ , then the locus of the circumcentre of $△ PQR$ is

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Answer:

Solution:

The circumcircle of $PQR$ has diameter joining $P$ to the circle centre $O = (0, 0)$ , so its centre is $P /2$ . For $P = (h, 4)$ , this is $(h /2, 2)$ .

Stream:JEESubject:MathematicsTopic:CircleSubtopic:General, Basic geometries, Definition Diametrical form of circle

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