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Mathematics - Circle Question with Solution | TestHub

MathematicsCircleEquation of chord with given middle point Chord of contact Pair of TangentsMedium2 minQB

MathematicsMediumnumerical

The chord of contact from a point on $x^{2} + y^{2} = 16$ to $x^{2} + y^{2} = r^{2}$ touches $x^{2} + y^{2} = 1$ . Find $∣ r ∣$ .

Answer:

2.00

Solution:

For point $(4 cos θ, 4 sin θ)$ the chord is $4 x cos θ + 4 y sin θ - r^{2} = 0$ . Its distance from the origin is $r^{2} /4 = 1$ , hence $∣ r ∣ = 2$ .

Stream:JEESubject:MathematicsTopic:CircleSubtopic:Equation of chord with given middle point Chord of contact Pair of Tangents

⏱ 2mℹ️ Source: QB

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